PH=-lg√Kac=-lg√(10^-14/1.8×10^-5×0.10)=5.13
Kh=10^-14/1.8*10^-5=5.6*10^-10[H+]=(0.10*5.6*10^-10)^1/2=7.5*10^-6mol/LpH=-lg[H+]=
