已知a^3+b^3=27,a^2b-ab^2=-6,求(b^3-a^3)+(a^2b-3ab^2)-2(b^3-ba^2)的值。

2024-12-15 02:30:48
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回答1:

(b^3-a^3)+(a^2b-3ab^2)-2(b^3-ba^2)
=b^3-a^3+a^2b-3ab^2-2b^3+2ba^2
=b^3-2b^3-a^3+a^2b+2a^2b-3ab^2
=-b^3-a^3+3a^2b-3ab^2
=-(b^3+a^3)+3(a^2b-ab^2)
=-27+3*(-6)
=-27-18
=-45