某同学用天平和量筒测量小石块的密度.(1)测量原理是______.(2)图甲为用天平测量小石块质量过程中的

2025-03-31 06:10:06
推荐回答(1个)
回答1:

(1)测量物质密度时,要先测出物体的质量与体积,然后由密度公式求出物质的密度,其实验原理是密度公式:ρ=

m
V

(2)把天平放到水平台上,此时应该进行的第一步操作是游码移到标尺左端的零刻度,并调节天平的平衡螺母使指针指到分度盘的中央;天平调节平衡后在称量时,右盘加入一定量的砝码,天平的指针偏向左侧,这时小石块的质量大于右盘中砝码的总质量,再加入5g的砝码后,指针偏向右侧,说明5g的砝码太大,应取下5g砝码,移动游码直至天平平衡;由由图甲(b)可知,游码的分度值是0.2g,小石块的质量是m=50g+20g+1.4g=71.4g;
(3)由图乙所示可知,小石块的体积V=60ml-30ml=30ml=30cm3
小石块的密度是ρ=
m
V
=
71.4g
30cm3
=2.38g/cm3=2.38×103kg/m3
故答案为:(1)ρ=
m
V
;(2)游码回零; 大于; 取下5g砝码,移动游码;71.4;(3)2.38×103

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