求((16s^2t^-6)⼀(25r^4))^-3⼀2

2024-12-16 09:16:33
推荐回答(1个)
回答1:

((16s^2t^-6)/(25r^4))^-3/2
=((4st^-3)/(掘橡5r^2))^(2*(-3/2))
=((橘雹4st^-3)/(5r^2)判伍旁)^(-3)
=125r^6/64s^3t^-9
=125r^6t^9/64s^3