已知函数f(x)=sin(2x+π⼀6)+sin(2x-π⼀6)-2cos^2x 1.f(x)的值域和最小正周期 2.y=f(x)的单调增区间

2025-02-01 02:57:53
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回答1:

f(x)=sin(2x+π/6)+sin(2x-π/6)-2cos^2x=√3sin2x+cos2x+1=2sin(2x+π/6)+1
1.f(x)的值域[-1,3],最小正周期π

kπ-π/3