java 中十进制与四进制互转代码【高分】

试试下面的代码，可以把10进制转换为2~36之间的任意进制，也可以把2~36之间的任意进制数转成10进制。

百度勿吞！！！

　　public class NumberToNumber {
　　public static String[] arr = {"0","1","2","3","4","5","6","7","8",
　　"9","A","B","C","D","E","F","G","H",
　　"I","J","K","L","M","N","O","P","Q",
　　"R","S","T","U","V","W","X","Y","Z"};
　　public static String numbers = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
　　public String tenToAll(int num,int base){
　　if(base < 2 || base > arr.length){
　　return String.valueOf(num);
　　}
　　String result = "";
　　do{
　　result = arr[num%base] + result;
　　num = (num - num%base)/base;
　　}while(num/base != 0);
　　result = num==0?result:arr[num] + result;
　　return result;
　　}
　　public int allToTen(String num,int base) throws Exception{
　　num = num.toUpperCase();
　　int d = 0;
　　int len = num.length();
　　for(int i=0;i　　char sub = num.charAt(i);
　　int val = numbers.indexOf(sub);
　　if(val == -1 || val > base){
　　throw new Exception();
　　}
　　d += val * Math.pow(base, len - i - 1);
　　}
　　return d;
　　}
　　public static void main(String[] args) {
　　NumberToNumber n = new NumberToNumber();
　　try {
　　String num = "123322";
　　int result = n.allToTen(num, 4);
　　System.out.println(result);
　　System.out.println(n.tenToAll(result, 4));
　　} catch (Exception e) {
　　System.err.println("非法数字!");
　　}
　　}
　　}

可以把10进制转换为2~36之间的任意进制，也可以把2~36之间的任意进制数转成10进制。

百度勿吞！！！

public class NumberToNumber {
public static String[] arr = {"0","1","2","3","4","5","6","7","8",
"9","A","B","C","D","E","F","G","H",
"I","J","K","L","M","N","O","P","Q",
"R","S","T","U","V","W","X","Y","Z"};
public static String numbers = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
public String tenToAll(int num,int base){
if(base < 2 || base > arr.length){
return String.valueOf(num);
}
String result = "";
do{
result = arr[num%base] + result;
num = (num - num%base)/base;
}while(num/base != 0);
result = num==0?result:arr[num] + result;
return result;
}
public int allToTen(String num,int base) throws Exception{
num = num.toUpperCase();
int d = 0;
int len = num.length();
for(int i=0;ichar sub = num.charAt(i);
int val = numbers.indexOf(sub);
if(val == -1 || val > base){
throw new Exception();
}
d += val * Math.pow(base, len - i - 1);
}
return d;
}
public static void main(String[] args) {
NumberToNumber n = new NumberToNumber();
try {
String num = "123322";
int result = n.allToTen(num, 4);
System.out.println(result);
System.out.println(n.tenToAll(result, 4));
} catch (Exception e) {
System.err.println("非法数字!");
}
}
}