解答：x²-3x+1=0∵ x≠0，两边同时除以xx-3+1/x=0x+1/x=3(x+1/x)²=9x²+1/x²+2=9∴ x²+1/x²=7∴ x³+1/x³ =(x+1/x)(x²-1+1/x²) =3*(7-1) =18
