求方程xy+lny-lnx=0所确定得隐函数y=f(x)的导数dy⼀dx

2024-12-31 21:45:09
推荐回答(1个)
回答1:

解:左右两边对x求导得y+x*y'+1/y*y'-1/x=0
则y'=(1/x-y)/(x+1/y)
即dy/dx=(1/x-y)/(x+1/y)