已知x的平方-5x+2000=0,那么[(x-2)的三次方-(x-1)的平方+1]⼀(x-2)等于多少?

2024-12-28 04:46:13
推荐回答(2个)
回答1:

[(x-2)的三次方-(x-1)的平方+1]/(x-2)
={(x-2)^3-x^2+2x-1+1}/(x-2)
=(x-2)^3/(x-2)-(x^2-2x)/(x-2)
=(x-2)^2-x
=x^2-4x+4-x
=x^2-5x+4
=x^2-5x+2000-1996
=0-1996
=-1996

回答2:

X无实数解

题目没写错吧??