若函数f(x)满足f(x+1)=x^2-2x,求f(2x+1)的解析式

突然忘记怎么做了!!
2024-12-25 23:22:12
推荐回答(3个)
回答1:

f(x+1)=x^2-2x
=(x+1)²-4x-1
=(x+1)²-4(x+1)+3
所以f(2x+1)=(2x+1)²-4(2x+1)+3
=4x²+4x+1-8x-4+3
=4x²-4x

回答2:

f(x+1) = (x-2)x
f(x) = (x-1)(x-3)
f(2x+1) = (2x-1)(2x-3) = 4x^2 -8x+3

回答3:

f(x+1)=(x+1)^2-4(x+1)+3
f(x)=x^2-4x+3
f(2x+1)=(2x+1)^2-4(2x+1)+3=4x^2-4x