x²-1=3x
x-1/x=3
两边平方
x²+X-²-2=9
X-²=11-x²
所以结果是11
x²-3x-1=0
两边同时除以x, x-3-1/x=0, x-1/x=3
x²+X-²=(x-1/x)^2+2=9+2=11
x^2-3x11=0
X^2=3X+1
X^2+X^(-2)
=X^2+1/X^2
=3X+1+1/X^2
=[X^2(3X+1)+1]/X^2
=[(3X+1)^2+1]/X^2
=(9X^2+6X+2)/X^2
=(9X^2+2X^2)/X^2
=11X^2/X^2
=11
x²=3x+1 代入x²+X-² = 3x+1+1/(3x+1)同分母得 原式=(9x²+6x+2)/(3x+1)再把x²=3x+1代入 得原式=11(3x+1)/(3x+1)=11
等于11
X=(3+13^0.5)/2或X=(3-13^0.5)/2
都带进去