已知:a+b=3,ab=1,求下列各式的值:(1)a^2b+ab^2 (2)a^2+b^2

2024-12-05 02:19:00
推荐回答(7个)
回答1:

(1)a^2b+ab^2
=ab(a+b)
=1×3
=3
(2)a^2+b^2
=(a+b)²-2ab
=3²-2×1
=9-2
=7

回答2:

1.a^2b+ab^2
=ab(a+b)又a+b=3,ab=1
所以
a^2b+ab^2
=1x3
=3
2.a+b=3
(a+b)^2=9
a^2+2ab+b^2=9
a^2+b^2=9-2ab
a^2+b^2=9-2=7
希望对你有帮助

回答3:

a^2b+ab^2 =ab(a+b)=1*3=3
a^2+b^2=a^2+2ab+b^2-2ab=(a+b)^2-2ab=1^2-2*3=-5

回答4:

a^2b+ab^2=ab(a+b)=3*1=3
a^2+b^2=(a+b)^2-2ab=3^2-2*1=7

回答5:

a^2b+ab^2=ab(a+b)=3
a^2+b^2=a^2+b^2+2ab-2ab=(a+b)^2-2ab=9-2=7

回答6:

(1)a^2b+ab^2=ab(a+b)=3
(2))a^2+b^2=(a+b)^2 -2ab=7

回答7:

ab(a+b)=3
(a+b)^2 - 2ab = 7