2/（x的平方+2x-3）-1/（1-x）=x-1/（x的平方-9）2/[(x+3)(x-1)+1/(x-1)=(x-1)/[(x+3)(x-3)两边同乘以(x+3)(x-3)(x-1)2*(x-3)+(x^2-9)=(x-1)^22x-6+x^2-9=x^2-2x+1 4x=16 x=4经检验：x=4是方程的根
