已知,2a+1=0,求代数式a(a-1)^2-a^2(a-4)+1的值

2024-12-23 03:27:03
推荐回答(2个)
回答1:

2a+1=0
a=-1/2
a(a-1)^2-a^2(a-4)+1
=a(a^2-2a+1)-a^3+4a^2+1
=a^3-2a^2+a-a^3+4a^2+1
=2a^2+a+1
将a=-1/2代入:
2x(-1/2)^2+(-1/2)+1
=2x1/4+1/2=1
故最后结果为1

回答2:

7