观察下列各式,1⼀6=1⼀2*3=1⼀2-1⼀3;1⼀12=1⼀3*4=1⼀3-1⼀4:1⼀20=1⼀4*5=1⼀4-1⼀5;1⼀30=1⼀

2024-12-31 02:16:42
推荐回答(2个)
回答1:

根据规律方程=1/(x-2)-1/(x-3)-[1/(x-1)-1/(x-3)]+1/(x-1)-1/(x-2)=0

回答2:

1/(x-2)(x-3)-1/(x-1)(x-3)+1/(x-1)(x-2)
=1/(x-2)-1/(x-3)-1/(x-1)+1/(x-3)+1/(x-1)-1/(x-2)
=0