在等比数列{an}中 (1) a4=27,q=-3,求a7 (2) a2=18,a4=8,求a1与q (3) a5=4,a,7=6求a9 (4) a5

求步骤
2024-12-16 13:35:33
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回答1:

解:
(1)
a7=a4q³=27×(-3)³=-729
(2)
a4/a2=q²=18/8=9/4
q=3/2或q=-3/2
q=3/2时,a1=a2/q=18/(3/2)=12
q=-3/2时,a1=a2/q=18/(-3/2)=-12
(3)
a5×a9=(a7/q²)×(a7q²)=a7²
a9=a7²/a5=6²/4=9