解二元一次方程组{3(x+y)-4(x-y)=4,x+y⼀2+x-y⼀6=1如题 谢谢了

要过程,快,XX
2024-12-30 16:46:10
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回答1:

3(x+y)-4(x-y)=4 (a) x+y/2+x-y/6=1 (b) 由a得:3x+3y-4x+4y=4 7y-x=4 x=7y-4 (c) 将c带入b得 7y-4+y/2+7y-4-y/6=1 14y-8+y/3=1 y=27/43 可得x=17/43