求解线性方程组的通解: 2X1+X2-X3+X4=1 4X1+2X2-3X3+X4=3 2X1+X2-3X3-X4=3

2024-12-15 21:12:25
推荐回答(1个)
回答1:

解: 增广矩阵 =
2 1 -1 1 1
4 2 -3 1 3
2 1 -3 -1 3

r2-2r1, r3-r1
2 1 -1 1 1
0 0 -1 -1 1
0 0 -2 -2 2

r1+r2, r3-2r2, r2*(-1)
2 1 0 2 0
0 0 1 1 -1
0 0 0 0 0

选 x1,x4 为自由未知量
通解为: (0,0,-1,0)+c1(1,-2,0,0)+c2(0, 2, 1,-1).