(a-b-c).(b+c-a)눀.(c-a+b)대怎么算,过程?

2024-11-25 19:29:48
推荐回答(2个)
回答1:

(a-b-c).(b+c-a)².(c-a+b)³
=(a-b-c)(a-b-c)²*【-(a-b-c)³】
=-(a-b-c)的6次方

回答2:

(a-b-c).(b+c-a)².(c-a+b)³
=(a-b-c)(a-b-c)²[-(a-b-c)³]
=-(a-b-c)^6