2x^4+x^3+7x^2+4x-4因式分解

2024-12-28 12:09:49
推荐回答(2个)
回答1:

2x^4+x^3+7x^2+4x-4
=2x^4+x^3-x^2+8x^2+4x-4
=x^2(2x^2+x-1)+4(2x^2+x-1)
=(x^2+4)(2x^2+x-1)
=(x^2+4)(2x-1)(x+1)

回答2:

2x^4+x^3+7x^2+4x-4
=2x^4+2x^3-x^3-x^2+8x^2+8x-4x-4
=2x³(x+1)-x²(x+1)+8x(x+1)-4(x+1)
=(x+1)(2x³-x²+8x-4)
=(x+1)[x²(2x-1)+4(2x-1)]
=(x+1)(2x-1)(x²+4)