乘积(1-1⼀2^2)(1-1⼀3^2)(1-1⼀4^2)......(1-1⼀2009^2)(1-1⼀2010^2)(1-1⼀2011^2)=_____?

请注意格式,过程。
2024-12-14 04:09:23
推荐回答(2个)
回答1:

乘积(1-1/2^2)(1-1/3^2)(1-1/4^2)......(1-1/2009^2)(1-1/2010^2)(1-1/2011^2)
=(1+1/2)(1-1/2)(1+1/3)(1-1/3)(1+1/4)(1-1/4)...(1+1/2009)(1-1/2009)(1+1/2010)(1-1/2010)(1+1/2011)(1-1/2011)
=(3/2)(1/2)(2/3)(4/3)(5/4)(3/4)...(2010/2009)(2008/2009)(2011/2010)(2009/2010)(2012/2011)(2010/2011)
=(1/2)(3/2)(2/3)(4/3)(3/4)(5/4)...(2008/2009)(2010/2009)(2009/2010)(2011/2010)(2010/2011)
(2012/2011)
=(1/2)(2012/2011)
=1006/2011

回答2:

(n+1)(n-1)/(n*n)

原式=(2+1)/2^2 *(3+1)(3-1)/3^2.....=(n+1)/(4*n)=1006/2011