C语言 学生成绩排序 按学生的序号输入 n 名学生的成绩,按照分数由高到低的顺序输出学生的名次、序号和成绩

2024-12-13 16:10:53
推荐回答(5个)
回答1:

#include 
#include 
typedef struct student
{
    int id;
    int score;
    struct student *next;
}STU;
int stuIndex;

void inputStuInfo(STU *stuHead);//输入学生信息
void orderStuInfo(STU *stuHead);//按照分数高到低顺序重组链表
void printStuInfo(STU *stuHead,int flag);//打印学生信息。参数flag=0:正常打印链表信息。flag!=0:打印排序后的名次信息
int main()
{
    STU *stuHead=(STU *)malloc(sizeof(STU));
    stuHead->next=NULL;
    stuIndex=1;
    inputStuInfo(stuHead);
    printf("--打印原始输入的链表!--\n");
    printStuInfo(stuHead,0);
    printf("--开始按分数降序排列!--\n");
    orderStuInfo(stuHead);
    printf("--链表按降序重组完成!--\n");
    printf("--打印降序排序的链表!--\n");
    printStuInfo(stuHead,1);
    return 0;
}
void orderStuInfo(STU *stuHead)
{
    STU *stuSave1=NULL,*stuSave2=NULL,stuSave3;
    stuSave1=stuHead;
    while(stuSave1->next!=NULL)//冒泡排序
    {
        stuSave2=stuSave1->next;
        while(stuSave2->next!=NULL)
        {
            if(stuSave1->next->scorenext->score)//交换成员值,保留原链表指针值
            {
                stuSave3=*(stuSave1->next);
                stuSave1->next->id=stuSave2->next->id;
                stuSave1->next->score=stuSave2->next->score;
                stuSave2->next->id=stuSave3.id;
                stuSave2->next->score=stuSave3.score;
            }
            stuSave2=stuSave2->next;
        }
        stuSave1=stuSave1->next;
    }
}
void printStuInfo(STU *stuHead,int flag)
{
    int i=1;
    while(stuHead->next!=NULL)
    {
        if(flag==0)
            printf("学生%d,成绩%d\n",stuHead->next->id,stuHead->next->score);
        else
            printf("第%d名,学生%d,成绩%d\n",i++,stuHead->next->id,stuHead->next->score);
        stuHead=stuHead->next;
    }
}
void inputStuInfo(STU *stuHead)
{
    int score;
    STU *stuNew=NULL,*stuTail=NULL;
    while(1)
    {
        printf("输入学生%d的成绩:(输入负数结束输入)",stuIndex);
        scanf("%d",&score);
        if(score<0)
            break;
        stuNew=(STU *)malloc(sizeof(STU));
        stuNew->score=score;
        stuNew->id=stuIndex;
        stuNew->next=NULL;
        if(stuHead->next==NULL)
            stuHead->next=stuNew;
        else
            stuTail->next=stuNew;
        stuTail=stuNew;
        stuIndex++;
    }
}

回答2:

#include 
#include 
typedef struct student
{
 int index; //学生的序号
 int score; //学生的成绩
}STUDENT_T;

//根据学生成绩进行冒泡排序
void ranking(STUDENT_T *a, int cnt)
{
 int i = 0;
 int j = 0;
 STUDENT_T tmp = {0};
 
 for (i = 0; i < cnt; i++)
 {
  for (j = i+1; j < cnt; j++)
  {
   if (a[i].score < a[j].score)
   {
    memcpy(&tmp, &a[j], sizeof(STUDENT_T));
    memcpy(&a[j], &a[i], sizeof(STUDENT_T));
    memcpy(&a[i], &tmp, sizeof(STUDENT_T));
   }
  }
 }
}

void main(int argc, char *argv[])
{
 int i = 0;
 int j = 0;
 int cnt = 0;
 int rank = 0;
 STUDENT_T student[1024] = {0};
 char tmp[32] = {0};
 
 printf("请输入学生人数:\n");
 scanf("%d", &cnt);
 if (cnt > 1024)
 {
  printf("最多1024个学生\n");
  return;
 }
  
 printf("请按序号依次输入%d个学生的成绩\n", cnt); 
 for (i = 0; i < cnt; i++)
 {
  printf("第%d个学生:\n", i+1);
  scanf("%s", tmp);
  student[i].index = i+1;
  student[i].score = atoi(tmp);
 }
 
 //根据成绩进行排名
 ranking(student, cnt);
 
 //计算名次并打印
 for (i = 0; i < cnt; i++)
 {
  //名次要考虑到并列的情况
  if (0 == i || student[i].score != student[i-1].score)
  {
   rank = i+1;
  }
  printf("名次:%d 序号:%d 成绩:%d\n", rank, student[i].index, student[i].score);
 }
}

回答3:

语文:88.5 数学:80 体育:66 英语:45.5 物理:40 化学:31 实验:30

回答4:

没有具体给出学生人数的话,最好用链表,
输出前可以先对链表按照分数排好序。
不用链表的话动态数组也行,静态数组的话,你定义的足够大也很好。就是浪费空间了。

自己百度吧,不难的。

回答5:

#include "stdio.h"
#include "stdlib.h"
struct student
{
int num;
int chengji;
};

void main()
{
struct student a[100],temp;
int n,i,j;
scanf("%d",&n);
for(i=0;i {
scanf("%d%d",&a[i].num,&a[i].chengji);
}
for(i=0;i for(j=0;j {
if(a[j+1].chengji>a[j].chengji)
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
}
}
for(i=0;i {
printf("%d %d %d\n",i+1,a[i].num,a[i].chengji);

}
}

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