高数定积分?

2025-03-14 13:29:46
推荐回答(3个)
回答1:

把sin三次方中分解出一个因式sinx来,凑到d后面去,变成dcosx,当然,积分要变成负的。因为dcosx=-sinxdx.
然后把分子剩下来的sin^2换成1-cos^2,这样的话,变积函数就变成两部分,一部分是1/cos^2, 一部分是-1,
得一部分得到-1/cosx,第二部分得到-cosx,综合第一步的负数,得到1/cosx+cosx,再分别代入上下限,得2根号2/3-2.

回答2:

回答3:

第一步:和的平方展开
(cosx+sin2x)^2
=(cosx)^2+(sin2x)^2+2sin2xcosx
第二步:二倍角公式
(cosx)^2+(sin2x)^2
=(1+cos2x)/2+(1-cos4x)/2
=1+(cos2x-cos4x)/2
第三步:积化和差公式
2sin2xcosx=sin3x+sinx
第四步:求积分函数的一个原函数
F(x)=x+sin2x/4-sin4x/8-cos3x/3-cosx
第五步:代入定积分上下限
F(π/2)=π/2+0-0-0-0=π/2
F(0)=0+0-0-1/3-1=-4/3
定积分结果为F(π/2)-F(0)=π/2+4/3。

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