推荐回答(4个)
可以星三角启动:
当负载对电动机启动力矩无严格要求又要限制电动机启动电流,电机满足380V/Δ接线条件,电机正常运行时定子绕阻接成三角形才能采用星三角启动方法。
相关条件:
1、容量7.5KW以上的三相异步电动机。
2、电动机在启动瞬间造成电网电压波动小于10%的,对于不经常启动的电动机可以放宽到15%;如果有专用变压器S变压器≥5P电机,电动机允许直接频繁启动。
3、满足经验经验公式:Ist/IN<0.75+ST\4PN
ST----公用变压器容量,KVA;
PN-----电动机额定功率,KW;
Ist/IN---电动机启动电流和额定电流之比。
4、星三角降压启动的电动机三相绕组共有六个外接端子:A-X、B-Y、C-Z(以下以额定电压380V的电机为例)A.星形启动:X-Y-Z相连,A、B、C三端接三相交流电压380V,此时每相绕组电压为220,较直接加380V启动电流大为降低,避免了过大的启动电流对电网形成的冲击。此时的转矩相对较小,但电动机可达到一定的转速。B.角形运行:经星形启动电动机持续一段时间(约几十秒钟)达到一定的转速后,电器开关把六个接线端子转换成三角形连接并再次接到380V电源时每相绕组电压为380V,转矩和转速大大提高,电动机进入额定条件下的运行过程。
原理:
1.当负载对电动机启动力矩无严格要求又要限制电动机启动电流且机电满足380V/Δ接线条件才能采取星三角启动方法;
2.该方法是:在机电启动时将机电接成星型接线,当机电启动成功后再将机电改接成三角型接线(通过双投开关迅速切换);
3.因机电启动电流与电源电压成正比,此时电网提供的启动电流只有全电压启动电流的1/3 ,但启动力矩也只有全电压启动力矩的1/3。
星三角启动,属降压启动他是以牺牲功率为代价来换取下降启动电流来实现的。所以不能一概而以机电功率的大小来肯定是不是需采取星三角启动,还的看是甚么样的负载,一般在需要启动时负载轻运行时负载重尚可采取星三角启动,一般情况下鼠笼型机电的启动电流是运行电流的5—7倍,而对电网的电压要求通常为正负10%(我纪忆中)为了不构成对电网电压过大的冲击所以要采取星三角启动,一般要求在鼠笼型机电的功率超过变压器额定功率的10%时就要采取星三角启动。只有鼠笼型机电才采取星三角启动。一家之言,姑且听之.
本人在实际使用进程中,发现需星三角降压启动的机电从11KW开始就有需要的,如风机、在启动时11KW电流在7⑼倍(100)A左右,按正常配置的热继电器根本启动不了,(关风门也没用)热继电器配大了又起不了保护机电的作用,所以建议用降压启动。而在一些启动负荷较小的机电上,由于机电到达恒速时间短,启动时电流冲击影响较小,所以在30KW左右的机电,选用1.5倍额定电流的断路器直接启动,长时间工作一点问题都没有。
网友1评论:星三角降压启动的电动机三相绕组共有六个外接端子:A-X、B-Y、C-Z(以下以额定电压380V的机电为例)
星形启动:X-Y-Z相连,A、B、C三端接三相交换电压380V,此时每相绕组电压为220,较直接加380V启动电流大为下降,避免了过大的启动电流对电网构成的冲击。此时的转矩相对较小,但电动机可到达一定的转速。
角形运行:经星形启动电动机延续一段时间(约几十秒钟)到达一定的转速后,电器开关把六个接线端子转换成三角形连接并再次接到380V电源时每相绕组电压为380V,转矩和转速大大提高,电动机进入额定条件下的运行进程。
能用,比泽尔15P高温机启动电流在50A左右,用星形分线圈启动就足够了
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