(1+1⼀2)(1+1⼀2^2)(1+1⼀2^4)(1+1⼀2^8)要过程

2025-01-03 05:19:01
推荐回答(2个)
回答1:

原式=2×(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
=2×(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
=2×(1-1/2^4)(1+1/2^4)(1+1/2^8)
=2×(1-1/2^8)(1+1/2^8)
=2×(1-1/2^16)
=2-1/2^15

回答2:

(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
=2*1/2(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
=2*(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)
=2*(1-1/2^16)
=2-1/2^15