一道微积分广义积分的题,求解!!!!!!!!!!!

2025-01-24 06:42:19
推荐回答(1个)
回答1:

变量替换x=asin^2t,t位于【0,pi/2】,dx=2asintcost,a-x=acos^2t,
原积分=积分(从0到pi/2)a^3sin^6t*根号(sin^2t/cos^2t)*2asintcostdt
=积分(从0到pi/2)2a^4sin^8tdt
=105pi/384*a^4