某矩形基坑,其底部尺寸为4×2米,开挖深度2.0米,坡度系数m=0.50,试计算其挖方量,若

2024-12-12 00:57:59
推荐回答(1个)
回答1:

[(4×2)+(4+2×0.5×2)×(2+2×0.5×2)]÷2×2=32m3
32×1.2÷2=18车