用因式分解法解一元二次方程(x-1)(x+2)=3(x+2)

2024-11-27 06:40:30
推荐回答(2个)
回答1:

简单啊(x-1)(x+2)=3(x+2)。移项得:(x-1)(x+2)-3(x+2)=0,提取公因式得(x+2)(x-4)=0,所以
x=-2 或。x=4

回答2:

(x-1)(x+2)=3(x+2)
(x-1)(x+2)-3(x+2)=0
(x+2)(x-1-3)=0
x+2=0,或x-4=0
x1=-2, x2=4