已知a+b=-4,ab=2,求多项式4a2b+4ab2-4a-4b的值

2025-02-01 12:00:37
推荐回答(3个)
回答1:

4a2b+4ab2-4a-4b
=4ab(a+b)-4(a+b)
=4(a+b)(ab-1)
=4×(-4)(2-1)
=-16

回答2:

4a²b+4ab²-4a-4b
=4ab(a+b)-4(a+b)
=4×2(-4)-4(-4)
=-32+16
=-16

回答3:

4a2b+4ab2-4a-4b
=4ab(a+b)-4(a+b)
=4(a+b)(ab-1)
=4*(-4)(2-1)
=-16;