解方程:1:x^2-4=0,2:x^2-2根号3x+3=0,3:(x-7)(2x+1)+7=0

要过程~!!!!!!
2025-01-02 13:29:32
推荐回答(2个)
回答1:

1:x^2-4=0,
(x-2)(x+2)=0
x=2或x=-2

2:x^2-2√3x+3=0,
(x-√3)^2=0
x=√3

3:(x-7)(2x+1)+7=0
2x^2-13x-7+7=0
2x^2-13x=0
x(2x-13)=0
x=0或x=13/2

回答2:

x^2-4=0
(x-2)(x+2)=0
x=2或x=-2

x^2-2根号3x+3=0
(x-√3)²=0
x-√3=0
x=√3

(x-7)(2x+1)+7=0
2x²-13x-7+7=0
2x²-13x=0
x(2x-13)=0
x=0或x=13/2