x^2+y^2-4x+6y+13=0x²-4x+4+y²+6y+9=0(x-2)²+(y+3)²=0x=2y=-3x-y=2+3=5 祝学习进步，望采纳~
X^2+Y^2-4X+6X+13=(X-2)^2+(Y+3)^2=0所以X=2,Y=-3x-y=2+3=5
(x+3)^2+(y-2)^2=0 => x=-3 y=2 x-y=-5
