若已知角α∈(0,π⼀2),利用三角函数线证明1<sinα+cosα<=根号2

主要是根号2哪里来的,附过程。谢谢
2024-12-31 15:55:00
推荐回答(3个)
回答1:

(sinα+cosα)^2=sina sina+cosa cosa +2sinacosa=1+sin(2a);
01<(sinα+cosα)^2<=2; sinα+cosα >0
1

回答2:

sinα+cosα=√2(sinαcosπ/4+cosαsinπ/4)=√2sin(α+π/4)

回答3:

sinα+cosα=√2(sinαcosπ/4+cosαsinπ/4)=√2sin(α+π/4)
∵α∈(0,π/2),∴α+π/4∈(π/4,3π/4),
√2/2<=sin(α+π/4)<=1
1<=√2sin(α+π/4)<=√2