α∈(π,3/2π), 所以可得:3π/2<π/2+a<2π所以可得: cos(π/2+a)=3/5cos(π/3-a)=cos[2π/3-(π/2+a)=cos2π/3cos(π/2+a)+sin2π/3sin(π/2+a)=-1/2x3/5+√3/2x(-4/5)=-(3+4√3)/10