若x-y=5,xy=6,求xy^2-x^2y与(x+y)^2的值

2024-12-28 15:09:19
推荐回答(6个)
回答1:

xy^2-x^2y
=xy(y-x)
=6×(-5)
=-30
(x+y)^2
=(x-y)²+4xy
=25+24
=49

回答2:

xy²-x²y=xy(y-x)=-(x-y)xy=6*(-5)=-30
(x+y)²=(x-y)²+4xy=5²+4*6=24+25=49
望采纳~~~~~~~

回答3:

xy^2-x^2y=xy(y-x)=6*5=-30
(x+y)^2=(x-y)^2+4xy=25+24=49
望采纳O(∩_∩)O~

回答4:

xy^2-x^2y=xy(x-y)=5*6=30
(x+y)^2=(x-y)^2+4xy=5^2+4*6=25+24=49

回答5:

x*y^2-x^2*y=xy*(y-x)=6*(-5)=-30
(x+y)^2=x^2+2xy+y^2=x^2-2xy+y^2+4xy=(x-y)^2+4xy=5^2+4*6=49

回答6:

xy^2-x^2y=-30
(x+y)^2=49