方程移项得：x^2+1/x^2+2x+2/x=1令t=x+1/x, 有：|t|>=1t^2=x^2+1/x^2+2方程化为：t^2-2+2t=1t^2+2t-3=0(t+3)(t-1)=0t=-3, t=1（舍去）所以x+1/x=-3x^2+3x+1=0x=(-3+√5)/2, (-3-√5)/2
