设u(x),v(x)均为可导函数y=√u눀(x)+v눀(x) 求dy⼀dx

2024-12-19 18:06:46
推荐回答(1个)
回答1:

y=√[u²(x)+v²(x)]
dy/dx=[2u(x)·u'(x)+2v(x)v'(x)]/{2√[u²(x)+v²(x)]}
=[u(x)·u'(x)+v(x)v'(x)]/√[u²(x)+v²(x)]