(2√3+3√2)的平方=30+12√6
(2√3+3√2)²=(2√3)²+2*2√3*3√2+(3√2)²=12+12√6+18=30+12√6 望采纳
(2√3+3√2)²=(2√3)²+2*2√3*3√2+(3√2)²=12+12√6+18=30+12√6
=(2√3)²+2×2√3×3√2+(3√2)²=12+12√6+18=30+12√6
30+12倍根号6
