f(x)=sin2x-根号下3cos2x+1
=2(sin2x×1/2-cos2x×根号下3/2)+1
=2(sin2xcosπ/3-cos2xsinπ/3)+1
=2sin(2x-π/3)+1
f(x)=sin2x-√3cos2x+1
f(x)=2(1/2sin2x-√3/2cos2x)+1
f(x)=2(cosπ/3sin2x-sinπ/3cos2x)+1
f(x)=2cos(2s-π/3)+1
不知
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