已知tana=-1⼀2,则2sinacosa⼀sin^2a-cos^2a的值是

2025-01-06 12:58:01
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回答1:

2sinacosa/(sin²a-cos²a)=sin2a/(﹣cos2a)=﹣tan2a=﹣2tana/(1-tan²a)
=﹣2×(﹣1/2)/[1-(﹣1/2)²]=1/(3/4)=4/3