1+1⼀2+1⼀4+1⼀8+1⼀16+……+1⼀(2的N次方)=?

2024-12-18 02:44:41
推荐回答(4个)
回答1:

1+1/2+1/4+1/8+1/16+……+1/(2的N次方)
=1+1-1/2^n
=2 - 1/2^n

回答2:

1+1/2+1/4+1/8+1/16+……+1/(2的N次方)
=1+【1-1/(2的N次方)】
=2-1/(2的N次方)

回答3:

1+(1-1/2)+(1/2-1/4)+(1/4-1/8)……=2-1/n²

回答4:

2-1/2^n