(1)(x눀-2y눀-z눀0-(-y눀+3x눀-z 눀)+(5x눀-y눀+2x눀)

2024-12-31 11:31:45
推荐回答(2个)
回答1:

最后一个括号应为 (5x²-y²+2z²)

(x²-2y²-z²) -(-y²+3x²-z²) + (5x²-y²+2z²)
= x²-2y²-z² + y²-3x²+z² + 5x²-y²+2z²
= 3x²-2y²+2z²

回答2:

(x²-2y²-z²)-(-y²+3x²-z ²)+(5x²-y²+2z²)
=x²-2y²-z²+y²-3x²+z ²+5x²-y²+2z²
=3x²-2y²+2z²