有这样一道题:“计算(2x^3-3x^2y-2xy^2)-(x^3-2xy^2+y^3)+(-x^3+3x^2y-y^3)的值,其中x=1⼀2,y=-1”

2025-01-02 10:33:26
推荐回答(2个)
回答1:

(2x^3-3x^2y-2xy^2)-(x^3-2xy^2+y^3)+(-x^3+3x^2y-y^3)
=2x^3 - 3x^3y-2xy^2-x^3+2xy^2-y^3-x^3+3x^2y-y^3
=2x^3-2x^3-2y^2
=-2y^2

回答2:

5654