先化简,再求值:2x-y+(2y^2-x^2)-(x^2-y^2),其中X=1,y=-1.

2024-12-28 06:26:40
推荐回答(2个)
回答1:

原式=3y^2-y-2x^2+2x
=3(y^2-1/3y+1/36)-2(x^2-x+1/4)+5/12
=3(y-1/6)^2-2(x-1/2)^2+5/12
代入x=1,y=-1
得 原式=4

回答2:

=2x-y+4y-2x-2x+2y
=5y-2x
=-5-2
=-7