[3(x-3)²-[2(x-5)²]=0(3x-9+2x-10)(3x-9-2x+10)=0(5x-19)(x+1)=0x1=19/5,x2=-1
9(X-3)^2-4(X-5)^2=0[3(x-3)-2(x-5)][3(x-3)+2(x-5)]=0(x+1)(5x-19)=0x=-1或x=19/5
(5x-19)(x+1)=0x=19\5x=-1