1、4(x-1)²=(x+1)²2(x-1)=x+1 或2(x-1)=-x-1x=3 或x=1/32、4(x-1)²-(x+1)²=0[2(x-1)+(x+1)][2(x-1)-(x+1)]=0(3x-1)(x-3)=0x=1/3 或x=33、4(x²-2x+1)=x²+2x+13x²-10x+3=0(3x-1)(x-3)=0x=1/3 x=3
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