根据正弦定理,a/sinA=c/sinC,sinC=(根号2)/4,余弦定理,cosA=(b^2+c^2-a^2)/(2bc),得b^2=18+2根号3,可得cosB=(6-根号3)/12>45,所以C为锐角,根据sinC求c即可答案:b=根号(18+2根号3) (自己化简吧)C=arcsin((根号2)/4) B=arccos((6-根号3)/12)