因式分解 X^4+3X^3+6X^2-4怎么解?急!!!

2024-12-24 16:27:56
推荐回答(2个)
回答1:

X^4+3X^3+6X^2-4
=X^4+3X^3+2X^2+4x²-4
=x²(x²+3x+2)+4(x²-1)
=x²(x+2)(x+1)+4(x+1)(x-1)
=(x+1)(x³+2x²+4x-4)

回答2:

(7X-4)(16-3X)=0 X1=7/4 X2=16/3 (3x 2)(x-4)=0 X1=-3/2 X2=4 9(2x 3)^2-4(2x-5)^2=0 (6X 9)^2-(4X-10)^2=