谁能帮我做这几道数学题啊？部分题要有过程！！！急需

2025-02-21 15:10:54

推荐回答（3个）

回答1：

1,1/2
2,(3+根号5）/2；（3-根号5）/2
3.k＜1
4.原式配方得（x+1/2）²-1/4-1=0 所以（x+1/2）²=5/4 所以 x=-1/2±（根号5）/2
5.原式移项得 8x²+10x-3=0 分解因式（4x-1)(2x+3)=0 所以 x=1/4,x=-3/2
6.原式化简为 4x²+10x+4=0,即 2x² +5x+2=0 所以（2x+1)(x+2)=0 解得 x=-1/2,x=-2
7.a=-4,b=-12. 所以 x²-ax+b=x²-4x-12=(x-2)(x+6)
8.x=0.x=1
9.x²-7x+6=0
10.0或8
11.设这个两位数十位为X，个位为Y。则 X+Y=5，(10x+y)(10y+x)=736 解得 xy=6
所以解得 X=2,Y=3. 或者 X=3,Y=2

回答2：

1、x1+x2=-1
x1*x2=m
由1/x₁ + 1/x₂=-2可得
x1+x2=-2x1*x2=-2m=-1
得m=1/2
2、x²-3x+1=（x-3/2）²-9/4+1=（x-3/2）²-5/4=0
得x-3/2=±根号5/2
得x=（3+根号5）/2或x=（3-根号5）/2
3、x²-2x+k=（x-1）²+k-1=0
（x-1）²=1-k
1-k＞0得k的取值范围为k＜1
4、x²+x-1=0
（x+1/2）²-5/4=0
x+1/2=±根号5/2
x=（根号5-1）/2或x=-（根号5+1）/2
5、8x²+10x=3
8x²+10x-3=0
（4x-1）（2x+3）=0
x=1/4或x=-3/2
6、（2x+1）²=-6x-3
(2x+4)(2x+1)=0
x=-2或x=-1/2
7、a=-6+2=-4
b=-6*2=-12
x²-ax+b
=x²+4x-12
=（x-2）*（x+6）
8、0或1
9、x²-5x+6=0
10、0或8
11、设个位为x，十位为5-x
则10（5-x）+x=50-9x
新的两位数为10x+5-x=9x+5
两数之积为（50-9x）（9x+5）=736
450x+250-81x²-45x=736
81x²-405x+486=0
x²-5x+6=0
x=2或x=3
得出原来的两位数有可能是23或32

算了这么多有点累了
能给点分就给点分吧
谢谢了

回答3：

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谁能帮我做这几道数学题啊 ？ 部分题要有过程！！！ 急需

谁能帮我做这几道数学题啊？部分题要有过程！！！急需