若a^2-5a+1=0,问:a+1⼀a的值是多少?a^2+1⼀a^2的值是多少?

2025-01-07 04:27:03
推荐回答(2个)
回答1:

a+1/a = a+(5a-a^2)/a = a+5-a=5
(a+1/a)^2 = a^2+1/a^2+2=25
a^2+1/a^2 = 23

回答2:

a^2-5a+1=0
两边同时除以a,得:
a-5+1/a=0
a+1/a=5

a^2+1/a^2
=(a+1/a)^2-2
=25-2
=23