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230问答网 > 石灰水与碳酸氢钙的反应有过量和少量之分吗?告诉我化学式和离子式吧

石灰水与碳酸氢钙的反应有过量和少量之分吗?告诉我化学式和离子式吧

2025-04-10 11:50:47

推荐回答（2个）

回答1：

不存在，方程式 Ca(OH)2 + Ca(HCO3)2 == CaCO3↓ + H2O，离子式是 OH-+HCO3-+Ca2+=CaCO3+H2O.这个方式决定因素在OH- 和HCO3的量，但是无论是什么样的比列，结果都一样，都是发生上述的反应

回答2：

不存在过量不过量的问题：
一个Ca(OH)2与2个Ca(HCO3)2反应：Ca(OH)2 + 2Ca(HCO3)2 == CaCO3↓ + Ca(HCO3)2 + 2H2O，消掉1个Ca(HCO3)2，方程为：Ca(OH)2 + Ca(HCO3)2 == CaCO3↓ + H2O，相当于二者等物质的量反应。

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